To solve this problem, we will apply the concepts related to the descriptive equations of linear motion that are related to the angular movement. Therefore we will have to:
Once the linear speed is defined as the distance traveled in a period of time (we will convert this period to international units) we will have to:
[tex]v = \frac{191}{1.9*3600}[/tex]
[tex]v = 0.028m/s[/tex]
The average distance of the two turning radii will indicate the moment when the turning speed is the same, therefore
[tex]r = \frac{11+35}{2}[/tex]
[tex]r = 23mm = 0.023m[/tex]
The relationship between the linear velocity and the angular velocity is given by the radius, since this is proportional to the linear velocity when multiplied by the angular velocity.
[tex]v = \omega r[/tex]
[tex]\omega = \frac{v}{r}[/tex]
[tex]\omega = \frac{0.028}{0.023}[/tex]
[tex]\omega = 1.22rad/s[/tex]
Therefore the common angular speed is 1.22rad/s
