wolflover32648p7r8rt wolflover32648p7r8rt
  • 02-01-2020
  • Mathematics
contestada

Find the zeros of the function in the interval [-2pi, 2pi] f(x)= -4sin x

Respuesta :

sam4040
sam4040 sam4040
  • 08-01-2020

Answer:

Zeros are [tex]x=-2\pi,-\pi,0,\pi,2\pi[/tex]

Step-by-step explanation:

[tex]f(x)=0\\-4\sin x=0\\\sin x=0\\[/tex]

[tex]\sin(-2\pi)=0\\\sin(-\pi)=0\\\sin(0)=0\\\sin(\pi)=0\\\sin(2\pi)=0[/tex]

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pingping19625
pingping19625 pingping19625
  • 02-11-2020

It's B) 0, ±pi, ±2pi on edge

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