saige1066
contestada

Jeff has 4 red pens and 2 blue pens in his backpack. He also has 1 yellow highlighter and 4 green highlighters in his
backpack. If he reaches into his backpack and grabs one pen and one highlighter without looking, what is the probability
that he will grab a blue pen and a yellow highlighter?

Respuesta :

TaeKwonDoIsDead

Answer:

[tex]\frac{1}{15}[/tex]

Step-by-step explanation:

In probability,

"AND" means "multiplication"

"OR" means "ADDITION"

We want probability of Blue Pen and Yellow Highlighter. So we find individual probabilities and "MULTIPLY" them.

Let P(b) be probability of blue pen

Let P(y) be probability of yellow highlighter

We know probability of event is that event divided by total number of that

So,

There are 4 + 2 = 6 pens

Blue pen = 2

Hence,

P(b) = 2/6 = 1/3

And,

There are 5 highlighters

Yellow highlighter = 1

Hence,

P(y) = 1/5

Now,

P(b and y) = 1/3 * 1/5 = 1/15

Hence,

probability of grabbing blue pen and a yellow highlighter is  [tex]\frac{1}{15}[/tex]

Viletkittykat

Answer:

2/15

Step-by-step explanation:

Otras preguntas