Answer: The change in temperature is 84.7°C
Explanation:
To calculate the change in temperature, we use the equation:
[tex]q=mc\Delta T[/tex]
where,
q = heat absorbed = 1 kCal = 1000 Cal (Conversion factor: 1 kCal = 1000 Cal)
m = mass of steel = 100 g
c = specific heat capacity of steel = 0.118 Cal/g.°C
[tex]\Delta T[/tex] = change in temperature = ?
Putting values in above equation, we get:
[tex]1000cal=100g\times 0.118cal/g^oC\times \Delta T\\\\\Delta T=\frac{1000cal}{100g\times 0.118cal/g^oC}\\\\\Delta T=84.7^oC[/tex]
Hence, the change in temperature is 84.7°C
The change in the temperature produced by the addition of 1 KCal of heat to 100 g of steel is 84.7 °C
From the question given above, the following data were obtained:
Mass of steel (M) = 100 g
Specific heat capacity of steel (C) = 0.118 Cal/gºC
Heat (Q) = 1 KCal = 1000 Cal
The change in the temperature of the steel can be obtained as follow:
1000 = 100 × 0.118 × ΔT
1000 = 11.8 × ΔT
Divide both side by 11.8
ΔT = 1000 / 11.8
Therefore, the change in the temperature of the steel is 84.7 °C
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