Answer:
Tension, T = 0.1429 N
Explanation:
Given that,
Mass of the rock, m = 0.0450 kg
Radius of the circle, r = 0.580 m
Angular speed, [tex]\omega=2.34\ rad/s[/tex]
The tension in the string is balanced by the centripetal force acting on it. It is given by :
[tex]T=\dfrac{mv^2}{r}[/tex]
Since, [tex]v=r\omega[/tex]
[tex]T=\dfrac{m(r\omega)^2}{r}[/tex]
[tex]T=\dfrac{0.0450\times (0.580\times 2.34)^2}{0.580}[/tex]
T = 0.1429 N
So, the tension in the string is 0.1429 N. Hence, this is the required solution.
