30.41 × 10²³ atoms
Explanation:
First we calculate the number of moles of carbon tetrachloride (CCl₄):
number of moles = mass / molar weight
number of moles of CCl₄ = 155.4 / 153.8 = 1.01 moles
Now to find the number of atoms in 155.4 grams of carbon tetrachloride we use Avogadro's number:
if in 1 mole of CCl₄ there are 5 × 6.022 × 10²³ atoms
then in 1.01 moles of CCl₄ there are X atoms
X = (1.01 × 5 × 6.022 × 10²³) / 1
X = 30.41 × 10²³ atoms
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Avogadro's number
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