Answer:
p-value= 0.27760
Step-by-step explanation:
Hello!
The RR apartment complex wants to decrease the proportion of tenants that pay their rent late. For this, they implemented the 6month pay on time and receive a Wal-Mart $50 gift card program.
If the historical proportion of tenants that pay on time is 85%, then the proportion of tenants that are late with their rent is 15%
If they want to test whether the proportion of the tenants that pay late decreased with the new program, the hypothesis is:
H₀: ρ ≥ 0.15
H₁: ρ < 0.15
α:?
The statistic is:
Z= ^ρ - ρ ≈ N(0;1)
√[(ρ(1 - ρ))/n]
If 44 out of 50 paid on time, this means that 6 paid late. Since for this hypothesis we are testing the proportion of people that paid late, these 6 tenants will be our number of "success"
The sample proportion is: ^ρ= 06/50 = 0.12
Z= 0.12 - 0.15 = -0.59
√[(0.15*0.85)/50]
The p-value is one-tailed (left) as the test:
P(Z ≤ -0.59) = 0.27760
I hope you have a SUPER day!