Vi walks 2 miles on first day, 2 miles on second day, 8 miles on third and fourth day and 1 mile on fifth day.
Step-by-step explanation:
Let,
x be the distance walked by Vi.
Therefore,
On first day = x
Second day = x
On days three and four,Vi walks twice as long as on the first two days
Third and fourth day = 2(x+x) = 2(2x) = 4x
On fifth day = half of first day = [tex]\frac{1}{2}x[/tex] = 0.5x
Total distance = 13 miles
Therefore,
[tex]x+x+4x+0.5x =13\\6.5x=13[/tex]
Dividing both sides by 6.5
[tex]\frac{6.5x}{6.5}=\frac{13}{6.5}\\x=2[/tex]
Distance on first day = x = 2 miles
second day = x = 2 miles
third and fourth day = 4x = 4(2) = 8 miles
fifth day = 0.5x = 0.5(2) = 1 miles
Vi walks 2 miles on first day, 2 miles on second day, 8 miles on third and fourth day and 1 mile on fifth day.
Keywords: distance, addition
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