Answer:
The ball will get upto the height of 3.26 meters.
Explanation:
Initial velocity of the ball = u = 8 m/s
final velocity of the ball = v = 0 m/s ( upward)
Acceleration due to gravity ,a= -g =[tex]-9.8 m/s^2[/tex]
Height of the ball when kicked = s
Using third equation of motion :
[tex]v^2-u^2=2as[/tex]
[tex](0 m/s)^2-(8 m/s)^2=2\times (-g)\times s[/tex]
[tex](0 m/s)^2-(8 m/s)^2=2\times (-9.8)\times s[/tex]
[tex]s=\frac{(-8 m/s)^2}{2\times -9.8 m/s^2}=3.26 m[/tex]
The ball will get upto the height of 3.26 meters.
