Answer: The correct answer is option B i.e., 2.78 mol
Explanation:
Aluminium reacts with iodine to form Aluminium iodide
[tex]$2Al(s)+3I_{2}(s) \to Al_{2}I_{6}(s)$[/tex]
From the equation, it is clear that 3 moles of iodine reacts with 2 moles of Aluminium to form Aluminium iodide
We know [tex]$No.\,of\,moles=\frac{weight}{molecular\,weight} \\[/tex]
For 2 moles of Aluminium, [tex]$2=\frac{weight}{27}$\\ $weight=2 \times 27=54g$[/tex]
3 moles of Iodine reacts with 54 g of Aluminium
? moles of iodine react with 50 g of Aluminium
[tex]$=\frac{3 \times 50}{54} =2.78 mol$[/tex]
