Respuesta :
Answer:
0.2g of hydrogen is needed to produce 1.80g of water
Explanation:
[tex]$H_{2}+O_{2} \to 2H_{2}O$[/tex]
No. of moles of water[tex]$= \frac{Weight}{Molecular \, weight}$ \\[/tex]
From given values,
Weight of water [tex]$=1.80g$[/tex]
Molecular weight of water [tex]$=18g$[/tex]
[tex]$\therefore$[/tex] No. of moles of water[tex]$=\frac{1.80}{18}=0.1 $[/tex]
From equation, it is clear that 2 moles of water can be formed by 2 moles of [tex]$H_{2}$[/tex]
Hence, 0.1 mole of water can be formed from 0.1 mole of [tex]$H_{2}$[/tex]
Now,
No. of moles of [tex]$H_{2} = \frac{Weight}{Molecular \, weight}$[/tex]
[tex]$\Rightarrow weight \,of\, H_{2}=No.\,of\,moles \times Molecular\,weight$\\ $=0.1 \times 2=0.2g$[/tex]
