Answer:
The alkyl bromide will be:1-bromo-2-methylpropane
The nitrile will be: 3-methylbutanenitrile
Explanation:
The hydrolysis of nitrile and its synthesis from alkyl halid is shown in the figure.
The target acid contains five carbons so we need a four carbon alkyl bromide which will give five carbon nitrile.
The alkyl bromide will be:1-bromo-2-methylpropane
We will react the alkyl bromide with NaCN to give nitrile.
The nitrile will be: 3-methylbutanenitrile
