Answer:
The height each brace reaches vertically is 10 feet
Step-by-step explanation:
Let
h -----> the height each brace reaches vertically in feet
d ----> the diagonal braces in feet
x ----> the horizontal distance in feet
Applying the Pythagoras Theorem
[tex]d^2=h^2+x^2[/tex]
we have
[tex]d=26\ ft\\x=24\ ft[/tex]
substitute
[tex]26^2=h^2+24^2[/tex]
Solve for h
[tex]h^2=26^2-24^2[/tex]
[tex]h^2=100[/tex]
[tex]h=10\ ft[/tex]
therefore
The height each brace reaches vertically is 10 feet
