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Dr. Chuck projects a ball horizontally from a lab bench. The ball lands on a bullseye marked on the floor a horizontal distance away. Compared to the time for the ball to simply drop vertically from the bench, the time in the air for Dr. Chuck's projected ball is?

Respuesta :

Answer:

in both the cases the time will be same

Explanation:

As we know that the chunk is projected horizontally

so here the initial speed of the chunk is given as

[tex]v_x = v_o[/tex]

[tex]v_y = 0[/tex]

now in order to reach the ball to the ground we can say

[tex]h = \frac{1}{2}gt^2[/tex]

so we will have

[tex]t = \sqrt{\frac{2h}{g}}[/tex]

now if another ball is just dropped from the same height then its initial speed is also zero in both direction

so again we have

[tex]y = \frac{1}{2}gt^2[/tex]

[tex]t = \sqrt{\frac{2h}{g}}[/tex]

so we can say that in both the cases the time will be same

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