Answer:
No, it did not slide
Explanation:
The acceleration of the vehicle is:
[tex]a = \frac{Vf^2-Vo^2}{2*d} =-4m/s^2[/tex]
We need to compare the friction force with the static friction force.
The magnitude of the friction force required for the mug not to slide is:
Ff = m*a = 0.5*4 = 2N
Now, the maximum static force is:
[tex]Fs = \mu s*N =\mu s*m*g=0.5*0.5*10=2.5N[/tex]
Since the maximum static force is greater than the required force, we can say that the mug didn't slide