Answer:
156.25 m
Explanation:
Given Acceleration, a = 0.50 m/s²
Time, t = 25 s
u = 0 m/s as trains starts from rest
Distance, s = ?
Using the Equation of motion as:
[tex]s=ut+\frac {1}{2}at^2[/tex]
t = Time taken
u = Initial velocity
s = Displacement
a = Acceleration
Applying the values as:
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times 25+\frac{1}{2}\times 0.50\times 25^2\\\Rightarrow s=0+0.5\times \frac{625}{2}\\\Rightarrow s=156.25\ m[/tex]
The train will go 156.25 m far.
