Respuesta :
Answer:
35.662 J/K is the entropy change when 1 mole of benzene melts at 5.5°C
Explanation:
The enthalpy of fusion for benzene = [tex]\Delta H_{fus}= 127.40 kJ/kg[/tex]
Molar mass of benzene = 78.0 g/mol
Or can be written as 1 mole of benzene = 78.0 g
1 g of benzene = [tex]\frac{1}{78.0 } mol[/tex]
[tex]\Delta H_{fus}[/tex]= 127.40 kJ/kg=127.40 kJ/1000 g (1kg = 1000 g)
[tex]=\frac{127.40 kJ}{1000 g}=\frac{127.40 kJ}{1000\times \frac{1}{78.0} mol}[/tex]
= 9.9372 kJ/mol = 9937.2 J /mol
The entropy change when 1 mole of benzene melts at 5.5°C:
[tex]\Delta S_{fus}=\frac{\Delta H_{fus}}{T}[/tex]
T = 5.5°C = 278.65 K
[tex]\Delta S_{fus}=\frac{9937.2 J /mol}{278.65 K}=35.662 J/K[/tex]
