Answer:
28.695 m/s
Explanation:
t = Time taken by the puck to fall the height
u = Initial velocity of the puck = 28 m/s
v = Final velocity of the puck
s = Displacement of the puck = 2 m
a = Acceleration due to gravity = 9.81 m/s²
Equation of motion
[tex]v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 2+28^2}\\\Rightarrow v=28.695\ m/s[/tex]
The speed with which the puck will hit the ground is 28.695 m/s
Answer:
6.26 m/s
Explanation:
they try to trick you by giving you the velocity in the x-axis but you are trying to find the velocity of the y-axis once it hits the ground.
Given:
Initial V₀ₓ= 28 m/s
inital V₍₀y₎ = 0 m/s
height = 2m
acceleration (gravity)= 9.8 m/s²
Find: final V₍y₎
V²-(V₀y)²=2as
V₀y = 0
∴ V²=2as
V²=2×(9.8 m/s²)(2m)
V = √39.2 m²/s²
V = 6.26 m/s
