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A force vector F1 points due east and has a magnitude of 200N. A second force F2 is added to F1. The resultant of the two vectors has a magnitude of 400N and points along the east/west line. Find the magnitude and direction of F2Source https://www.physicsforums.com/threads/physics-trigonometry.61160/

Respuesta :

Answer:

The second vector [tex]\vec{F_2}[/tex] points due West with a magnitude of 600N

Explanation:

The original vector [tex]\vec{F_1}[/tex] points with a magnitude of 200N due east, the Resultant vector [tex]\vec{R}[/tex] points due west (that's how east/west direction can be interpreted, from east to west) with a magnitude of  400N. If we choose East as the positive direction and West as the negative one, we can write the following vectorial equation:

[tex]\vec{F_1}+\vec{F_2}=\vec{R}\implies\vec{F_2}=\vec{R}-\vec{F_1}=-400N-200N=-600N[/tex]

With the negative sign signifying that the vector points west.