Answer:
a) v = 35 cm/s
Explanation:
Here the work done by gravity on two masses is equal to the change in kinetic energy of the two masses
so here in m = 150 g mass moves down then other mass M = 250 g will move up by same distance on inclined plane
so we have
[tex]mgd - Mgsin\theta d= \frac{1}{2}mv^2 + \frac{1}{2}Mv^2[/tex]
here we know that
[tex]m = 150g[/tex]
[tex]M = 250 g[/tex]
[tex]\theta = 30 degree[/tex]
[tex]d = 10 cm = 0.10m[/tex]
so we will have
[tex](0.150)9.81\times 0.10 - (0.250)9.81sin30\times 0.10 = (\frac{1}{2}(0.150) + \frac{1}{2}(0.250))v^2[/tex]
[tex]0.0245 = 0.2 v^2[/tex]
[tex]v = 0.35 m/s[/tex]
