Answer: The probability that hat both televisions work= 0.1837
The probability at least one of the two televisions does not work=0.8163
Step-by-step explanation:
Given : Total televisions = 7
Defective televisions = 4
The proportion of defective sets : [tex]p=\dfrac{4}{7}[/tex]
Number of televisions selected = 2
Using binomial probability formula :
[tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex]
The probability that hat both televisions work. :_
[tex]P(x=0)=^2C_0(\dfrac{4}{7})^{0}(1-\dfrac{4}{7})^{2}=(\dfrac{3}{7})^{2}=0.183673469388\approx0.1837[/tex]
The probability at least one of the two televisions does not work:-
[tex]P(x\geq1)=1-P(x=0)=1-0.1837=0.8163[/tex]
