contestada

Assume that the stopping distance of a van varies directly with the square of the speed. A van traveling 40 miles per hour can stop in 70 feet. If the van is traveling 48 miles per​ hour, what is its stopping​ distance?

Respuesta :

Answer:

d = 100.8 ft

Explanation:

As we know that initial speed of the van is 40 miles then the stopping distance is given as 70 feet

here we know that

[tex]v_f^2 - v_i^2 = 2 ad[/tex]

so here we have

[tex]0^2 - 40^2 = 2 a (70 feet)[/tex]

now again if the speed is increased to 48 mph then let say the stopping distance is "d"

so we will have

[tex]0^2 - 48^2 = 2 a (d)[/tex]

now divide the above two equations

[tex]\frac{40^2}{48^2} = \frac{70 feet}{d}[/tex]

[tex]d = 100.8 ft[/tex]

Otras preguntas