Respuesta :
Answer:
2
Step-by-step explanation:
In general, [tex](a+b)(a-b)=a^2-b^2[/tex].
So we have here that:
[tex]437=21^2-x^2[/tex]
[tex]437=441-x^2[/tex]
We went [tex]-x^2[/tex] by itself first.
Subtract 441 on both sides:
[tex]437-441=-x^2[/tex]
[tex]-4=-x^2[/tex]
Multiply both sides by -1:
[tex]4=x^2[/tex]
Take the square root of boht sides:
[tex]\pm \sqrt{4}=x[/tex]
[tex]\pm 2=x[/tex]
So both 2 and -2 would satisfy the equation.
Only one of these is a whole number.
The whole numbers consist of the elements that you can count with and 0.
The whole number set is {0,1,2,3,4,5,6,7,...}
So 2 is the answer.
Check:
Replace x with 2:
437=(21+2)(21-2)
437=(23)(19)
437=437 is a true equation so 2 is definitely a solution.
