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A roller with a length of 2m and a diameter of 1m is flattening a playground. It is necessary for the roller to make 500 full revolutions in order to completely flatten the playground. What is the area of the playground?

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mnhlabatsi7

Answer:

6282 [tex]m^{2}[/tex]

Step-by-step explanation:

First lets find the length of the whole field if we assume the roller goes in one continuous straight route. Basically that will be 500 circumferences in length.

length of the field = 2πr^2 * 500

                             = 2π * 1 m * 1 m *500

                             =3141 m

Area = 3141 m * 2 m

        = 6282 [tex]m^{2}[/tex]

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