Answer:
A) Apparent Weight = 590 N
Explanation:
As we know that frequency is given as
[tex]f = \frac{1}{30}[/tex]
[tex]f = 0.033 Hz[/tex]
now the angular speed is given as
[tex]\omega = 2\pi f[/tex]
[tex]\omega = 2\pi(0.033) = 0.21 rad/s[/tex]
now at the top position we will have
[tex]mg - N = m\omega^2 R[/tex]
[tex]N = mg - m\omega^2 R[/tex]
[tex]N = 600 - \frac{600}{9.8}(0.21)^2(4.0)[/tex]
[tex]N = 590 N[/tex]