Answer:
Speed of the car after the collision is 1.2 m/s
Explanation:
It is given that,
Mass of first car, m₁ = 2 kg
Velocity of first car, v₁ = 6 m/s
Mass of second car, m₂ = 3 kg
Velocity of second car, v₂ = -2 m/s (it is travelling in opposite direction)
The two cars lock together and move along the road. This shows an inelastic collision. Let their common velocity is V. On applying the conservation of momentum as :
[tex]m_1v_1+m_2v_2=(m_1+m_2)V[/tex]
[tex]V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}[/tex]
[tex]V=\dfrac{2\ kg\times 6\ m/s+3\ kg\times (-2\ m/s)}{5\ kg}[/tex]
V = 1.2 m/s
So, after collision the speed of the cars is 1.2 m/s. Hence, this is the required solution.
