Answer:
The acceleration and charge are 17.122 m/s² and [tex]8.6\times10^{-5}\ C[/tex]
Explanation:
Given that,
Mass of object = 0.8 g
Electric field = 159 N/C
Distance = 72 m
Time = 2.9 s
We know that,
The electric force is
[tex]F = Eq[/tex]....(I)
The newton's second law
[tex]F=ma[/tex]
Put the value of F in the equation (I)
[tex]ma=Eq[/tex]...(II)
We calculate the acceleration
Using equation of motion
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
[tex]a =\dfrac{2s}{t^2}[/tex]
[tex]a=\dfrac{2\times72}{(2.9)^2}[/tex]
[tex]a=17.122\ m/s^2[/tex]
From equation (II)
[tex]q=\dfrac{ma}{E}[/tex]
[tex]q=\dfrac{0.8\times10^{-3}\times17.122}{159}[/tex]
[tex]q=0.000086148427673\ C[/tex]
[tex]q=8.6\times10^{-5}\ C[/tex]
Hence, The acceleration and charge are 17.122 m/s² and [tex]8.6\times10^{-5}\ C[/tex]
