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A Carnot heat engine has an efficiency of 0.200. If it operates between a deep lake with a constant temperature of 293.0 K and a hot reservoir, what is the temperature of the hot reservoir? O 352 K O 1760 K O 366 K 1470 K

Respuesta :

Answer:

366 K

Explanation:

T₀ = Constant Temperature of deep lake = 293.0 K

T = Temperature of hot reservoir  connected to carnot engine = ?

η = Efficiency of Carnot engine during the operation

Efficiency of Carnot engine is given as

[tex]\eta = 1-\frac{T_{o}}{T}[/tex]

Inserting the values

[tex]0.200 = 1-\frac{293.0}{T}[/tex]

T = 366 K

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