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Determine the length of a copper wire that has a resistance of 0.172 ? and cross-sectional area of 7.85 × 10-5 m2. The resistivity of copper is 1.72 × 10-8 ?·m.

Respuesta :

Answer:

Length of copper wire, l = 785 meters

Explanation:

Given that,

Resistance of the copper wire, R = 0.172 ohms

Area of cross section, [tex]A=7.85\times 10^{-5}\ m^2[/tex]

Resistivity of copper, [tex]\rho=1.72\times 10^{-8}\ \Omega-m[/tex]

The resistance of a wire is given by :

[tex]R=\rho\dfrac{l}{A}[/tex]

[tex]l=\dfrac{RA}{\rho}[/tex]

[tex]l=\dfrac{0.172\ \Omega\times 7.85\times 10^{-5}\ m^2}{1.72\times 10^{-8}\ \Omega-m}[/tex]

l = 785 meters

So, the length of the copper wire is 785 meters. Hence, this is the required solution.

The length of copper wire will be  l = 785 meters

what will be the length of the copper wire?

It is given that,

Resistance  R = 0.172 ohms

Area of cross-section,

[tex]A=7.85\times10^5 m^2[/tex]

The resistivity of copper,

[tex]\rho=1.72\times10^{-8} \Omega m^-1[/tex]

So the resistance of the copper wire will be

[tex]R=\dfrac{\rho l}{A}[/tex]

[tex]l=\dfrac{RA}{\rho}[/tex]

Now putting the values

[tex]l=\dfrac{0.172\times7.85\times10^{-5}}{1.72\timews10^{-8}}[/tex]

[tex]l=785\ meters[/tex]

Thus the length of copper wire, will be  l = 785 meters

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