Answer:
180 m
Explanation:
The rock follows a free-fall motion - so the vertical distance covered can be found by using the equation
[tex]h=\frac{1}{2}gt^2[/tex]
where
g = 10 m/s^2 is the acceleration due to gravity
t = 6.00 s is the time of the fall
Substituting these data, we find the height of the cliff:
[tex]h=\frac{1}{2}(10 m/s^2)(6.00 s)^2=180 m[/tex]
