ANSWER
[tex]9(\pi - \frac{ \sqrt{3} }{2} )[/tex]
Approximately, A=20
EXPLANATION
The circle has radius r=3 units.
The height of the triangle is ,
[tex]h = 6 \cos(60 \degree) = 3[/tex]
The base of the triangle is
[tex]b = 6 \sin(60 \degree) = 3 \sqrt{3} [/tex]
The area of the triangle is
[tex] \frac{1}{2} bh[/tex]
[tex] = \frac{1}{2} \times 3 \sqrt{3} \times 3[/tex]
[tex] = \frac{9}{2} \sqrt{3} [/tex]
The area of the circle is
[tex]\pi {r}^{2} [/tex]
[tex] = {3}^{2} \pi[/tex]
[tex] = 9\pi[/tex]
The difference between the area of the circle and the triangle is
[tex]9\pi - \frac{9}{2} \sqrt{3} = 9(\pi - \frac{ \sqrt{3} }{2} )[/tex]
