Answer:
[tex]1.0313\cdot 10^{12}[/tex]
Explanation:
The net charge is given by the sum of the charges of the protons and of the electrons:
[tex]Q=N_p q_p + N_e q_e[/tex]
where we have
[tex]Q=-5.00 nC=-5.00\cdot 10^{-9}C[/tex] is the net charge
[tex]N_p = 1.0\cdot 10^{12}[/tex] is the number of protons
[tex]q_p = +1.6\cdot 10^{-19}C[/tex] is the charge of one proton
[tex]N_e[/tex] is the number of electrons
[tex]q_e = -1.6\cdot 10^{-19}C[/tex] is the charge of one electron
Solving the equation for [tex]N_e[/tex], we find the number of electrons:
[tex]N_e = \frac{Q-N_p q_p}{q_e}=\frac{-5.0\cdot 10^{-9}C-(1.0\cdot 10^{12})(1.6\cdot 10^{-19}C)}{-1.6\cdot 10^{-19}C}=1.0313\cdot 10^{12}[/tex]
The number of electrons is 1.03*10^12.
Data;
Using quantization of charge
[tex]Q=(-5*10^-^9)-(1.6*10^-^7)= number of electron\\number of electron = \frac{-1.65*10^-^7}{-1.6*10^-^1^9}=1.03*10^1^2electrons[/tex]
The number of electrons is 1.03*10^12.
Learn more on quantization of charge here;
https://brainly.com/question/14661130
