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Jim had 92 more marbles than Sam. After Sam gave Jim 18 marbles, Jim had twice as many marbles as Sam. How many marbles did Jim have at first?

Respuesta :

Answer:

238

Step-by-step explanation:

let the number of marbles Sam has be x, then

Jim has x + 92 ← 92 more than Sam

After swap of 18 marbles

Sam has x - 18 and sam has x + 92 + 18 = x + 110

Jim now has twice as many as Sam, that is

x + 110 = 2(x - 18)

x + 110 = 2x - 36 ( subtract x from both sides )

110 = x - 36 ( add 36 to both sides )

146 = x

At first Jim had 146 + 92 = 238 marbles

brownie48

Answer is 27.5

= 92+18

=110 divided by 2

=55

Haha this is wrong