50 POINTS! Chipping from the rough, a golfer sends the ball at an angle of 54° with an initial velocity of 13m/s, how far down the green did the ball go?

Respuesta :

Range equation:

[tex]x=\dfrac{{v_i}^2\sin2\theta}g[/tex]

This ball travels a distance of

[tex]x=\dfrac{\left(13\frac{\rm m}{\rm s}\right)^2\sin108^\circ}{9.8\frac{\rm m}{\mathrm s^2}}=16\,\mathrm m[/tex]