Answer: V = 6.30L
PV = nRT
15°C = 15+273 = 288K
3.75*V = 1.50*0.082057*288
V = (1.50*0.082057*288)/3.75
V = 6.30L
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The approximate value of the volume of the gas is 958.3L
Using the ideal gas equation which is a combination of pressure law, Boyle's law and Charles's law.
Mathematically
[tex]PV=nRT[/tex]
we convert the value of temperature from degree Celsius to Kelvin.
To do this, simply add 273.15 to the °C value.
[tex]T=15 + 273.15 = 288.15K[/tex]
From the data given, we can substitute into the equation and solve for v
[tex]PV = nRT\\3.75*V=1.5*8.314*288.15\\3.75V=3593.52\\V=\frac{3593.52}{3.75}\\V=958.27L[/tex]
The approximate value of the volume is 958.3L
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