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An ordinary fair die is a cube with the numbers 1 through 6 on the sides. Imagine that such a die is rolled twice in succession and that the faces of the 2 rolls are added together. This sum is recorded of single trial of a random experiment. Event A: The sum is greater than 6 Event B the sum is divisible by 6

Respuesta :

Answer:

A. 5/9    B. 1/6.

Step-by-step explanation:

Total possible events = 6*6 = 36.

A.  The possible combinations for the sum  being <= 6 are:

1 ,1  2,2   3,3   1,2  1,3  1,4  1,5  2,1   2,3  2,4  3,1   3,2  3,3  4,1  4,2  5,1

= 16

So Probability of Sum > 6 =  (36-16) / 36

= 20/36

= 5/9.

B.   Possible combinations where the sum is divisible by 6  are

3,3  2,4  4,2  1,5  5,1. 6,6   =   6.

So the required probability =  6/36

= 1/6.

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