Answer:
40 W
Explanation:
The maximum wattage (power) that Mike can use is given by:
[tex]P=VI[/tex]
where
V is the voltage
I is the maximum current
In this problem, we have:
[tex]V=120 V[/tex] is the voltage
[tex]I=\frac{1}{3}A=0.33 A[/tex] is the maximum current available
Therefore, the maximum power that could be used is
[tex]P=VI=(120 V)(0.33 A)=40 W[/tex]
