contestada

If the speed of sound in the air is 340 m/s, the length of the organ pipe, open at both ends, that can resonate at the fundamental frequency of 136 Hz, would be:

Respuesta :

Answer:

1.25 m

Explanation:

For an open-air pipe, the two ends of the pipe corresponds to two antinodes of the standing wave; therefore, the wavelength of the wave is equal to twice the length of the tube:

[tex]\lambda=2 L[/tex]

We can rewrite the wavelength using the speed of the sound wave, v, and the frequency, f:

[tex]\lambda=\frac{v}{f}[/tex]

And substituting into the previous equation we get

[tex]\frac{v}{f}=2L\\L= \frac{v}{2f}[/tex]

And using

v = 340 m/s

f = 136 Hz

We find the length of the organ pipe:

[tex]L=\frac{340 m/s}{2(136 Hz)}=1.25 m[/tex]