contestada

Which of the following equations is equivalent to 4[x + 2(3x – 7)] = 22x – 65?

28x – 7 = 22x – 65

28x – 56 = 22x – 65

10x – 14 = 22x – 65

16x – 28 = 22x – 65

Respuesta :

kudzordzifrancis

Answer:

[tex]28x-56=22x-65[/tex]

Step-by-step explanation:

The given equation is

4[x + 2(3x – 7)] = 22x – 65

We expand the inner parenthesis to get;

[tex]4[x+6x-14]=22x-65[/tex]

Simplify the expression on the right hand side.

[tex]4(7x-14)=22x-65[/tex]

Expand using the distributive property to get;

[tex]28x-56=22x-65[/tex]

tramserran

Answer:   b) 28x - 56 = 22x - 65

Step-by-step explanation:

4[x + 2(3x - 7)] = 22x - 65

start with the "inside" parenthesis: (distribute 2 into 3x - 7)

4[x + 6x - 14] = 22x - 65

add the like terms that are inside the parenthesis:

4[7x - 14] = 22x - 65

distribute 4 into 7x - 14:

28x - 56 = 22x - 65

Otras preguntas