Hey there!
Assuming you meant: [tex]\bold{(x-2)^2=49}[/tex]
If so, then follow these steps
- Firstly, lets [tex]\bold{subtract}[/tex] by the number [tex]\bold{49}[/tex] on each of the sides that you're working with
- [tex]\bold{x^2-4x+4-4-49}[/tex] [tex]\bold{=49-49}[/tex]
- [tex]\bold{Cancel: 49-49}[/tex] because it gives you the result of [tex]\bold{0}[/tex]
- [tex]\bold{Keep: 4-49}[/tex] because it helps us solve for our answer
- [tex]\bold{We}[/tex] [tex]\bold{get:}[/tex] [tex]\bold{x^2-4x-45=0}[/tex]
2. [tex]\bold{Factor}[/tex] out the left side of your equation
- [tex]\bold{(x+5)(x-9)=0}[/tex]
3. [tex]\bold{Set}[/tex] the numbers to the number [tex]\bold{0}[/tex]
- [tex]\bold{x+5=0}[/tex]
- [tex]\bold{x-9=0}[/tex]
- First one: [tex]\bold{x=-5}[/tex]
- Second one: [tex]\bold{x=9}[/tex]
- Since you don't have any options of [tex]\bold{x=-5}[/tex] we can't use that one an [tex]\bold{x-value}[/tex]
So, [tex]\boxed{\boxed{\bold{Answer: E.)x=9}}}[/tex]
Good luck on your assignment and enjoy your day!
~[tex]\bold{LoveYourselfFirst:)}[/tex]
