Alex4530
contestada

The distance, in feet, two boys travel per second on a treadmill is shown to the left. which comparison is accurate? A. Xavier is traveling at 1.5 feet per second.
B. Moises is going faster than Xavier
C. The difference in their rates of change is 1 foot per second.
D. If both boys remain in the treadmill for 10 minutes, Xavier will have traveled a greater distance.

The distance in feet two boys travel per second on a treadmill is shown to the left which comparison is accurate A Xavier is traveling at 15 feet per secondB Mo class=

Respuesta :

CalaverEsc

Xavier:

15/2 = 7.5 feet/s

Moises:

5/1 = 5 feet/s


Therefore, A is incorrect, B is incorrect and C is incorrect, so the answer is D

grujan50

Answer:

Rates of change from Xavier is bigger then rates of change from Moises

Vx > Vm

Step-by-step explanation:

From this graph we can calculate the velocity ( which is rates of change) or feet per second

Velocity of Xavier is:

Vx = 15 / 2 = 7.5 ft/sec

Velocity of Moises is:

Vm = 15 / 3 = 5 ft/sec

We can see that velocity Vx is bigger than Vm, which means that

Vx > Vm

God with you!!!

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