Respuesta :
8.60*10^23 / 6.02*10^23 (# of atoms in one mole) = 1.43 moles
1.43*26.98 (atomic mass of Al. In other words, this is how much one mole of Al atoms weighs in grams) =
38.54g
38.54g is how much this piece of foil would weigh.
1.43*26.98 (atomic mass of Al. In other words, this is how much one mole of Al atoms weighs in grams) =
38.54g
38.54g is how much this piece of foil would weigh.
Answer: The mass of foil is 38.6 grams.
Explanation:
According to mole concept:
[tex]6.022\time 10^{23}[/tex] number of particles are contained in 1 mole of an element.
1 mole of aluminium has a mass of 27 g
We are given:
Number of aluminium atoms = [tex]8.60\times 10^{23}[/tex]
To calculate the mass of given number of atoms, we use unitary method:
[tex]6.022\time 10^{23}[/tex] number of particles has a mass of 27 grams
So, [tex]8.60\times 10^{23}[/tex] number of particles has a mass of [tex]\frac{27}{6.022\times 10^{23}}\times 8.60\times 10^{23}=38.6g[/tex]
Hence, the mass of foil is 38.6 grams.