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Which postulate or theorem proves △FWJ∼△PKJ ? AA Similarity Postulate SAS Similarity Theorem SSS Similarity Theorem Triangle F W J with right angle W and triangle P K J with right angle K. Points W, J, and K are collinear. W J is 10 centimeters and K J is 5 centimeters. Angle F J W is labeled 63 degrees and angle J P K is labeled 27 degrees.

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Answer:

AA Similarity Postulate  proves △FWJ∼△PKJ

Step-by-step explanation:

It is given that,

△FWJ and △PKJ are two right angled triangle.

In △FWJ right angled ate W  and in △PKJ right angled at K.

Therefore <W = < K

To find angles of ΔFWJ

In △FWJ , <FJW = 63°  then <WFJ = 90° - 63° = 27°∼△PKJ

To find angles of ΔPKJ

In △PKJ, <JPK = 27° then <PJK = 90°-27° = 63°

According to this information AA Similarity Postulate  proves that

△FWJ∼△PKJ

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