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The chess club is selling drinks during the track and field event. The club purchased water, juice boxes, and pouches of lemonade for the event. They spent $138.52 on juice boxes and $75 on lemonade. The club purchased three cases of water. Each case of water cost $6.80. What was the total cost of drink? 10 points

Respuesta :

KazooManKory

Answer:

$233.92

Step-by-step explanation:

So we need to find the price of all the water they bought first. We can do this by multiplying the number of case by cost per case. Let x be the total price of the water.

6.80*3=x

Multiply

20.40=x

They paid $20.40 for water. To find the total price we need to add how much they spent on water, juice, and lemonade. Let y be this number.

20.40+138.52+75=y

Add these up

233.92=y

They paid $233.92 for the drinks

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