Respuesta :

Rinkhals

We know that :

[tex]\heartsuit[/tex]  nth term of a Arithmetic Sequence is given by : a + (n - 1)d

where : a is the first term

d is the common difference, which is given by difference between 2nd term and 1st term

Given Sequence : 15 , 23 , 31 , 39. . . . .  .

We can notice that : a = 15

d = 2nd term - 1st term = (23 - 15) = 8

⇒ 61st term : 15 + (61 - 1)8

⇒ 15 + (60)8

⇒ 15 + 480

⇒ 495

⇒ 61st term of the given sequence is 495

MrGumby

Answer:

The 61st term would be 495

Step-by-step explanation:

In order to find the 61st term, you need to find the rule for the sequence. You'll notice that the numbers are going up by 8. Since there is no 0th term, the first term would be 8 more than the base.

15 - 8 = 7

Therefore the base is 7. As a result, you can model the sequence as:

An = 8n + 7

In which n is the number in the sequence. Now knowing this, we can plug in 61 and get the answer.

An = 8n + 7

An = 8(61) + 7

An = 488 + 7

An = 495

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