[tex]y + 2 < \frac{1}{4}x-1[/tex] First I want to isolate "y", by subtracting 2 on both sides
[tex]y < \frac{1}{4}x-3[/tex]
This is similar to slope-intercept form:
y = mx + b
"m" is the slope, "b" is the y-intercept (the y value when x = 0) or (0,y)
The only difference is that the sign is not an equal sign.
When the sign is ≤ or ≥ ("less/greater than or equal to"), the line is a solid line
When the sign is < or >, the line is a dotted line.
When y is > (greater than), the shaded area is above the line.
When y is < (less than), the shaded area is below the line.
[tex]y < \frac{1}{4}x-3[/tex]
Slope: 1/4 [so you go up 1 unit, and to the right 4 units]
y-intercept: -3 or (0,-3)
Since the sign is <, the line is a dotted line.
Since y is <, the shaded area is below the line
