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The difference of the square of a number and 16 is equal to 6 times that number. Find the negative solution.

Respuesta :

let's say that number is "x".


[tex]\bf \stackrel{\textit{difference of \underline{x} and 16}}{x^2-16}=\stackrel{\textit{6 times \underline{x}}}{6x}\implies x^2-6x-16=0 \\\\\\ (x-8)(x+2)=0\implies x= \begin{cases} 8\\ \boxed{-2} \end{cases}[/tex]

quacktheboy

Answer:

Answer is -2

Step-by-step explanation: I got it right lol

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