Respuesta :

An acid donates [tex] H^{+} [/tex] ion in aqueous solution. A base accepts [tex] H^{+} [/tex] ion in aqueous solution.

The equation representing the acid base reaction of [tex] HC_{2}O_{4}^{-} [/tex] and [tex] HS^{-} [/tex]:

[tex] HC_{2}O_{4}^{-}(aq) + HS^{-}(aq) ----> H_{2}C_{2}O_{4}(aq)+S^{2-}(aq) [/tex]

In the above reaction, as [tex] HC_{2}O_{4}^{-} [/tex] acts as a base it is accepting the hydrogen ion from [tex] HS^{-} [/tex]. Similarly, [tex] HS^{-} [/tex] donates its hydrogen ion to [tex] HC_{2}O_{4}^{-}[/tex] acting as an acid.

The acid donates a proton to the base in an acid - base reaction.

According to the Brownstead - Lowry definition, an acid is any substance that donates a proton while a base is any substance that accepts a proton. Hence, if HS− acted as a acid, then it must have donated a proton. If HC2O4− acted as the base, then it accepted a proton.

Therefore, the acid base reaction between HC2O4− and  HS− in which  HS− acted as the acid and HC2O4− acted as the base is;

HC2O4−(aq) +  HS−(aq) -----> H2C2O4(aq) + S−(aq)

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