The diameter of a carbon atom is 1.54 å. (a) express this diameter in picometers. (b) how many carbon atoms could be aligned side by side in a straight line across the width of a pencil line that is 0.20 mm wide

Respuesta :

Answer: -

(a) 1.54 x 10² pm

(b) 1.3 x 10⁶ is the number of carbon atoms could be aligned side by side in a straight line across the width of 0.2 mm.

Explanation: -

1 å = 10² pm

Diameter of a carbon atom = 1.54 å = 1.54 x 10² pm

1 mm = 10⁹ pm

Total distance = 0.2 mm = 0.2 x 10⁹ pm

Number of carbon atoms could be aligned side by side in a straight line across the width = Total distance / Diameter of a carbon atom

= [tex] \frac{0.2 x 109 pm}{1.54 x 102 pm} [/tex]

= 1.3 x 10⁶

In a 0.2 mm width, 1.3 x 10⁶ carbon atoms could be aligned side by side in a straight line. The diameter of a carbon atom is 1.54 x 10² pm

What is an Angstrom (Å)?

An angstrom is a unit of measurement of the length which is equal to the [tex]\bold {10^{-10} \ m}[/tex].

1 [tex]\bold {\AA}[/tex] = 10² pm

Thus,

Diameter of a carbon atom = 1.54  [tex]\bold {\AA}[/tex] = 1.54 x 10² pm

B)

Since, 1 mm =  10⁹ pm

Thus,

Total distance = 0.2 mm = 0.2 x 10⁹ pm

So,

[tex]\bold {Number \ of \ Carbon \ atoms = \dfrac {0.2 x 10^9} {1.54 x 10^2}} \\\\\bold {Number \ of \ Carbon \ atoms = 1.3 x 10^6}[/tex]

Therefore,  In a 0.2 mm width, 1.3 x 10⁶ carbon atoms could be aligned side by side in a straight line.

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