we have given that length of a rectangle is 13 cm less that five times its width.
where l is length and b is width.
we need to set up an equation according to the problem statement.
l=5b-13
we have area =28cm^2
we know that l*b=28
(5b-13)*b=28
5b^2-13b-28=0
we need to solve it by formula
we get (5b-20)(5b+7)=0
b=4 and b=-7/5 so negative value cannot be chosen so b=4
and l=5b-13=20-13=7.
l=7
